| Wednesday 22 September 2004 6:34:37 am 
                                                                
                                                                 Hi all, I have a PHP script on another server with the following content: 
<?php /* grabs the POST variables and puts them into variables that we can use */
 $relatieCode=$_POST['relatieCode'];
 echo("code:".$relatieCode."");
 ?>
 I have a clickable image in Exponential, which should open the PHP script and pass the user-id of the logged in user as 'relatieCode'. Unfortunately I don't know how to pass the user-id. In my eZ template I've got the following code: 
{let user=fetch( 'user', 'current_user' )}{$user.contentobject.name}
 {$user.email}
 {$user.login}
 {/let}
 <form method="POST" action="http://mysite.com/myform.php" name="form">
 <input type="hidden" name="relatieCode" id="relatieCode" value={$user.login}>
 <input type="image" name="formbutton" onClick="return validate(form)" SRC={"buttons/bt_contact.png"|ezimage} class=button alt="My alt text">
 </form>
 In my eZ site I can see the right user id (user.login), so the fetch is OK. But my PHP script doesn't show the user ID. When I change:  <input type="hidden" name="relatieCode" id="relatieCode" value={$user.login}> into  <input type="hidden" name="relatieCode" id="relatieCode" value="MYVALUE"> then my PHP script does show 'MYVALUE'. Can anyone please tell me what I'm doing wrong?  Thanks, Maarten UPDATE; Sorry, my bad: I closed the let too early... |